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Q.

In a sample of excited hydrogen atoms electrons make transition from n = 2 to n = 1. Emitted photons strike on a metal of work function $(ϕ)$ 4.2 eV. Calculate the wavelength (in A°) associated with ejected electrons having maximum kinetic energy.

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answer is 5.

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Detailed Solution

$n_{2} \to n_{1}, E = hc \bar{v} = hcR (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$
= hcR(3/4)

K.E. = hcR(3/4) – 4.2 eV

= 6 ev

$λ = \sqrt{\frac{150}{K . E}}$

On solving $λ$ = 5A⁰

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