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Q.

In a sample of rock, the ratio of  206Pb to  238U nuclei is found to be 0.5. The age of the rock is (Given half life of U238decay to =4.5×109 year and answer if initially the rock had equal nuclei of 206Pb and  238U)

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a

4.5×109  ln  3  year

b

2.25×109  year

c

4.5×109  ln  32ln2  year

d

2.25×109  ln32  year

answer is C.

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Detailed Solution

NPbNUr=12 NUrNPb=2 NUrN0=23 23=12n 32=2n ln(32)=n  ln2 ln(32)=tT  ln2 t=Tln(3/2)ln(2)

t=4.5×109ℓn(3/2)ℓn(2)

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