Q.

In a saturated solution of the sparingly soluble strong  electrolyte AgIO3(molecular mass = 283) the equilibrium which sets is AgIO3(s)Ag+(aq)+IO3(aq)If the solubility product constant Ksp of AgIO3at a given temperature 1.0×108what is the mass of  AgIO3 contained in 100 ml of its saturated solution? 

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a

1.0×107g

b

1.0×104g

c

28.3×102g

d

2.83×103g

answer is C.

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Detailed Solution

Let s = solubility  
AgIO3Ag++IO3 Ksp=Ag+IO3=s×s=s2  Given Ksp=1×108  s=Ksp=1×108 =1.0×104mol/lit=1.0×104×283g/lit  Molecular mass of AgIO3=283 =1.0×104×283×1001000gm/100ml =2.83×103gm/100ml

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