In a school having 200 students, 120 play foot ball, 70 play cricket, and 60 play both. The number of students play neither football nor cricket is

$n\left(F\cap C\right)=60$

$n\left(F\cup C\right)=n\left(F\right)+n\left(C\right)-n\left(F\cap C\right)$

$=120+70-60$

$=130$

Number of students neither play foot ball nor play cricket

$=n\left(\mu \right)-n\left(F\cup C\right)$

$=200-130$

$=70$