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In a series electrical circuit comprising a resistor made up of a metallic wire, the ammeter reads $100 mA$ . If the length of the wire is doubled, the change in current flowing through the circuit is [[1]] $mA$ .

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Detailed Solution

If the length of the wire is doubled, the change in current flowing through the circuit is

50 mA

.
It is known that the resistance of the wire is directly proportional to the length of the wire. Mathematically,

R \propto l

Therefore, the resistance of the wire will also be doubled as the length of the wire is doubled.

R_{1} = R

and

R_{2} = 2 R

.
Also, the current is inversely proportional to the resistance and therefore the current will become half when the resistance is doubled. The ammeter reading is,

I = \frac{100}{2}

\Rightarrow I = 50 mA

The ammeter reading is

50 mA

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