Q.

In a series LCR circuit, a resistor of 300 Ω, a capacitor of 25 nF and an inductor of 100 mH are used. For maximum current in the circuit, the angular frequency of the ac source is _____ × 104 radians s–1.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For maximum current in a series LCR circuit, the resonance condition must be satisfied. The resonant angular frequency ω0\omega_0 is given by:

ω0=1LC\omega_0 = \frac{1}{\sqrt{LC}}

Step 1: Given Data

Resistance R=300ΩR = 300 \Omega (not needed for resonance frequency calculation),

Capacitance C=25C = 25 nF =25×109= 25 \times 10^{-9} F,

Inductance L=100L = 100 mH =100×103= 100 \times 10^{-3} H.

Step 2: Calculate Resonant Angular Frequency ω0\omega_0

ω0=1LC\omega_0 = \frac{1}{\sqrt{L C}}

Substituting the values:

ω0=1(100×103)×(25×109)\omega_0 = \frac{1}{\sqrt{(100 \times 10^{-3}) \times (25 \times 10^{-9})}}

 =12500×106 =10650=2×104 rad/s

 

 ω0=2×104 rad/s 

Final Answer:

2

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon