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In a series LCR circuit $R = 300 Ω, L = 60 mH, C = 0.50 μF$ an alternating voltage of 50V and angular frequency 10000 rad /sec is applied to it. The phase difference between the current and the voltage is

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$37 °$

$45 °$

$90 °$

$53 °$

answer is B.

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Detailed Solution

$X_{L} = L ω = 60 \times 10^{- 3} \times 10^{4} = 600 Ω; X_{C} = \frac{1}{ω C} = \frac{1}{5 \times 10^{- 7} \times 10^{4}} = 200 Ω$

$ϕ = {Tan}^{- 1} (\frac{600 - 200}{300}) = {Tan}^{- 1} (\frac{4}{3}) = 53^{\circ}$

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