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Q.

In a series LR circuit with XL=R.  Power factor is P1.  If a capacitor of capacitance  C with  XC=XL is added to the circuit the power factor becomes P2.  The ratio of P1  to P2  will be:

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a

1:3

b

1:2

c

1:2

d

1:1

answer is B.

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Detailed Solution

P=RZP1=RR2+XL2=RR2(asXL=R)

P1=12

P2=RR2+(XL-XL)2=P2=1

P1=1

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