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Q.

In a series resonant LCR circuit, the voltage across R is 100V and $R = 1 kΩ$ with $C = 2 μF$ . The resonant frequency $ω$ is 200 rad/s. At resonance the voltage across L in volt is

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a

250V

b

200V

c

350V

d

120V

answer is A.

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Detailed Solution

At resonance $X_{L} = X_{C}$

$I = \frac{V_{R}}{R} = \frac{100}{1000} = 0.1 A$
$V_{L} = {IX}_{L} = {IX}_{C} = \frac{I}{ωC} = \frac{0 .1}{200 \times 2 \times 10^{- 6}} = 250 V$

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In a series resonant LCR circuit, the voltage across R is 100V and R=1kΩ with C=2μF . The resonant frequency ω is 200 rad/s. At resonance the voltage across L in volt is