In a series spectrum of hydrogen, the wavelength of radiation is 6,563A0. The name of the series and the orbits in which electronic transition takes place is

v¯=1λ=RH122-132=5RH36λ=365RH365912A0=6563 A0

In a series spectrum of hydrogen, the wavelength of radiation is 6,563A0. The name of the series and the orbits in which electronic transition takes place is

v¯=1λ=RH122-132=5RH36λ=365RH365912A0=6563 A0

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In a series spectrum of hydrogen, the wavelength of radiation is 6,563A⁰. The name of the series and the orbits in which electronic transition takes place is

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answer is A.

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$\bar{v} = \frac{1}{λ} = R_{H} (\frac{1}{2^{2}} - \frac{1}{3^{2}})$

$= \frac{5 R_{H}}{36}$

$λ = \frac{36}{5 R_{H}}$

$\frac{36}{5} (912 A^{0})$ =6563 A⁰

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In a series spectrum of hydrogen, the wavelength of radiation is 6,563A0. The name of the series and the orbits in which electronic transition takes place is

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In a series spectrum of hydrogen, the wavelength of radiation is 6,563A⁰. The name of the series and the orbits in which electronic transition takes place is