Q.

In a simple pendulum experiment, the time in seconds taken for 20 oscillations is noted in 5 trials as 39.2, 38.4, 40.8, 41.4, 40.2, then the average frequency is

Easy

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0.5 s

$2 s^{- 1}$

2 s

$0 .5 s^{- 1}$

answer is D.

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Detailed Solution

Time taken for 20 oscillations
$\frac{39 .2 + 38 .4 + 40 .8 + 41 .4 + 40 .2}{5} = \frac{200}{5} = 40 s$
Time taken for one oscillation $= \frac{40}{20} = 2 s$
i.e., Time period 2 s
frequenc $= \frac{1}{Time period} = \frac{1}{2} = 0 .5 s^{- 1}$

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