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In a single throw of a die, the probability of getting a multiple of $3$ is:

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\frac{1}{2}

\frac{1}{3}

\frac{1}{6}

\frac{3}{4}

answer is B.

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Detailed Solution

Given a dice is thrown once.
Possible outcomes on rolling a dice are

1, 2, 3, 4, 5, 6

.
Total number of outcomes n(S)=6.
Out of the possible outcomes, multiple of

3

are

3

and

6

.
Favorable outcomes n(E)=2.
Probability

= \frac{n (S)}{n (E)}

\Rightarrow \frac{2}{6}

\Rightarrow \frac{1}{3}

Therefore, option (2) is correct.

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