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In a slide calipers,(m+1) number of vernier divisions is equal to m number of smallest main scale divisions. If d is the magnitude of the smallest main scale division, then the vernier constant is

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$\frac{d}{m + 1}$

$\frac{d}{m}$

$\frac{md}{m + 1}$

$\frac{(m + 1) d}{m}$

answer is A.

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Detailed Solution

$\begin{array}{l} (M + 1) VSD = MMSD \\ 1 MSD = d \\ L.C = 1 MSD - 1 VSD \\ = d - \frac{Md}{M + 1} \\ = \frac{d}{M + 1} \end{array}$

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