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In a small village of Jharkhand, Panjunia (name of the village), there was a blacksmith. He made different types of $3 D$ solid shapes. One day he got an order from Ramu for making of $14 c m$ long cylindrical rods of $2 c m$ radius. He had solid iron boxes whose dimensions were $20 c m × 16 c m × 11 c m$ .How many rods Ramu will get from one solid box.

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20

rod

25

rod

35

rod

17

rod

answer is D.

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Detailed Solution

Given by,
Height of the cylindrical rod is

14 cm

Radius of the cylindrical rod is

2 cm

.
Solid iron box dimension,
Length is

20 cm

.
Breath is

16 cm

.
Height is

11 cm

.
Cylindrical rod is

2 π r r + h

Substituting a given value in the above equation,
We get,
Cylindrical rod

= 2 × 227 × 2 2 + 14

Simplified as,

= 2 × 227 × 216 c m 2

Volume of Cuboid

= l b h

Volume of the cuboid

= 20 c m × 16 c m × 11 c m

Number of cylindrical rods obtained by the iron box

= Volume of cuboid Cylinderical rod

= 20 c m × 16 c m × 11 c m = 2 × 227 × 2 × 16

Simplified above equation,We get

17

rods.
Hence the number of cylindrical rods obtained by the iron box is

17

rods.

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