In a solid AB having the NaCl structure. ‘A’ atoms occupy the corners of the cubic unit cell. If all the edge centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

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A₂B

A₄B₃

AB₂

A₃B₄

answer is D.

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Detailed Solution

So, "A" takes up 8 of the cubic unit cell's corners, which each add 1/8 to the cube.
Therefore = 8*1/8=1
Additionally, 6 face-centered atoms make up half of this cube.
Therefore, 6*1/2=3
The total contribution of atom "A" is therefore 4
Currently, B resides in octahedral voids (NaCl structure), contributing 1/4.
Therefore, 1+12*1/4=4
The equation is thus A₄B₄ or AB.
All of the face-centered atoms are now being removed along one axis (any axis origin at centre of cube)
Consequently, 2 atoms were removed from the cube.
Therefore, the contribution from "A" is still 8*1/8 (corner atoms) + 4*1/2 (face-centered atoms) = 3.

Therefore the correct option is D A₃B₄

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