In a standard YDSE setup, we plot the phase difference $(ϕ)$ between both waves at point P on the screen against the angular position $(θ)$ of point P on the screen. The graph is as shown blow.
Choose the correct statement(s)

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The first maxima above the centre is at $θ = \frac{π}{6}$

There are a total of 4 minima on the screen

The distance $S_{1} S_{2} = 2 λ$

At $θ = \frac{π}{3},$ intensity is minimum

answer is A, B, C.

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Detailed Solution

From 2^nd graph, when $*, ϕ = 4 π = 2 λ =$ distance between $S_{1} a n d S_{2}$
$A t θ = \frac{π}{6}, ϕ = d \sin θ = 2 λ \frac{l}{2} = λ$ $∴$ Intensity is maximum.

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