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In a step-up transformer, the turn ratio is 1 : 10. A resistance of $200 Ω$ connected across the secondary is drawing a current of 0.5 A. What is the primary voltage and current?

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25 V, 4 A

50 V, 1 A

20 V, 2 A

10 V, 5 A

answer is B.

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Detailed Solution

$N_{p} : N_{s} = 1 : 10 and V_{s} = 0 .5 \times 200 = 100 V$

$\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}} \Rightarrow \frac{100}{V_{p}} = \frac{10}{1} \Rightarrow V_{p} = 10 V$

$\frac{i_{p}}{i_{s}} = \frac{N_{s}}{N_{p}} \Rightarrow \frac{i_{p}}{0 .5} = \frac{10}{1}, i_{p} = 5 A$

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