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In a thermodynamic process, fixed mass of a gas is changed in such a manner that the gas release 20 J of heat and 8 J of work was done on the gas. If the initial internal energy of the gas was 30 J, the final internal energy will be

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58 joule

18 joule

42 joule

2 joule

answer is B.

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Detailed Solution

(2) According to first law of thermodynamics,

$∆ Q = ∆ U + ∆ W ∆ Q = h e a t a b s o r b e d b y g a s ∆ W = w o r k d o n e b y g a s - 20 J = ∆ U - 8 J ∆ U = - 12 J = U_{F i n a l} - U_{i n i t i a l} U_{i n i t i a l} = 30 J U_{F i n a l} = 30 - 12 = 18 J$

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