In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by $T ∆ X$ , where T is temperature of the system and $∆ X$ is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas $X = \frac{3}{2} R \ln (\frac{T}{T_{A}}) + R \ln (\frac{V}{V_{A}})$ . Here, R is gas constant, V is volume of gas, $T_{A} and V_{A}$ are constants.
The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.
List - I List - II
I) Work done by the system in
process $1 \to 2 \to 3$ P) $\frac{1}{3} {RT}_{0} \ln 2$
II) Change in internal energy in
process $1 \to 2 \to 3$ Q) $\frac{1}{3} {RT}_{0}$
III) Heat absorbed by the system in
process $1 \to 2 \to 3$ R) ${RT}_{0}$
IV) Heat absorbed by the system in
process $1 \to 2$ S) $\frac{4}{3} {RT}_{0}$
T) $\frac{1}{3} {RT}_{0} (3 + \ln 2)$
U) $\frac{5}{6} {RT}_{0}$

Question

Accepted Answer

Detailed Solution

	List - I		List - II
I)	Work done by the system in process $1 \to 2 \to 3$	P)	$\frac{1}{3} {RT}_{0} \ln 2$
II)	Change in internal energy in process $1 \to 2 \to 3$	Q)	$\frac{1}{3} {RT}_{0}$
III)	Heat absorbed by the system in process $1 \to 2 \to 3$	R)	${RT}_{0}$
IV)	Heat absorbed by the system in process $1 \to 2$	S)	$\frac{4}{3} {RT}_{0}$
		T)	$\frac{1}{3} {RT}_{0} (3 + \ln 2)$
		U)	$\frac{5}{6} {RT}_{0}$