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Q.

In a thermodynamic process pressure of a fixed mass of gas is changed in such a manner that the gas releases 30 joule of heat and 18 joule of work was done on the gas. If the initial internal energy of the gas was 60 joule, then the final internal energy will be

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a

72 joule

b

96 joule

c

32 joule

d

48 joule

answer is B.

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Detailed Solution

dQ=-30 J ; dW=-18 J ; Ui=60 J

Uf-Ui=dQ-dW

⇒Uf=Ui+dQ-dW=60-30+18=48 J

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