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Q.

In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, then the internal energy wiII be

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a

80 J

b

-20 J

c

20 J

d

30 J

answer is B.

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Detailed Solution

Here dQ = d + dW
$\begin{array}{l} dU = U_{f} - U_{i} \\ ∴ dQ = (U_{f} - U_{i}) + dW \end{array}$
or $\begin{array}{l} U_{f} = dQ + U_{i} - dW \\ dQ = - 30 J \end{array}$
(heat is rejected by system)
$\begin{aligned} U_{i} = 40 J and dW = - 10 J \\ ∴ U_{f} = - 30 + 40 + 10 = 20 J \end{aligned}$

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In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, then the internal energy wiII be