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Q.

In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules gives out 30 J of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be

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a

40 J

b

30 J

c

20 J

d

60 J

answer is B.

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Detailed Solution

ΔQ=ΔU+ΔW=Uf−Ui+ΔW
⇒−30=Uf−40−10⇒Uf=20

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