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Q.

In a third order determinant, each element of the first column consists of sum of three terms, each element of the second column consists sum of four terms, each element of the third column consists of sum of 10 terms, then it can be decomposed into n! determinants then n=

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a

120

b

6

c

4

d

5

answer is B.

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Detailed Solution

The number of determinats =3x4x10=120
∴ n!=120=5!
∴ n = 5

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