In a titration certain amount of ${\mathrm{H}}_2{\mathrm{O}}_2$ is treated with y moles of ${\mathrm{KMnO}}_4$ in acidic medium. The left out ${\mathrm{KMnO}}_4$ when treated with $X^{+}$ in basic medium oxidizes $X^{+1}$ to $X^{+6}$ and $0.2M, x\mathrm{L}$ of $X^{+}$ was consumed. The mole of given ${\mathrm{H}}_2{\mathrm{O}}_2$ solution is :