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Q.

In a titration of $H_{2} O_{2}$ certain amount is treated with 'y' mole of ${KMnO}_{4}$ in acidic medium. The mole of $H_{2} O_{2}$ in solution will be :

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a

2y

b

$\frac{5 y}{2}$

c

5y

d

3y

answer is B.

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Detailed Solution

The mole of hydrogen peroxide in the solution can be given as,

$n \times 2 = y \times 5$

So, $n = 5 y / 2$

Thus, option B is correct.

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