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In a transistor, a change of 5mA in the emitter current produces a change of 4.95mA in the collector current. The base current changes by

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25µA

50µA

75µA

100µA

answer is B.

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Detailed Solution

$W e k n o w, I_{E} = I_{B} + I_{C}$

$\Rightarrow Δ I_{E} = Δ I_{B} + Δ I_{C}$

$\Rightarrow 5 = Δ I_{B} + 4.95$

$\Rightarrow Δ I_{B} = 0.05 m A = 50 x 10^{- 6} A = 50 µ A$

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