In a transistor, a change of 8mA in the emitter current produces a change of 7.9mA in the collector current. The base current changes by

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1000 μA

100 μA

1μA

10 μA

answer is C.

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Detailed Solution

$\begin{array}{l} I_{E} = I_{B} + I_{C} [A s p e r j u n c t i o n l a w] \\ \Rightarrow Δ I_{E} = Δ I_{B} + Δ I_{C} \\ \Rightarrow 8 = Δ I_{B} + 7.9 \\ \Rightarrow Δ I_{B} = 0.1 m A = 100 μ A \end{array}$

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