In a transistor if ICIE=α and ICIB=β. If α varies between 2021 and 100101, then the value of β lies between

β=α1−αβ=20211-2021=20β=1001011-100101=100so β lies between 20-100

In a transistor if ICIE=α and ICIB=β. If α varies between 2021 and 100101, then the value of β lies between

β=α1−αβ=20211-2021=20β=1001011-100101=100so β lies between 20-100

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In a transistor if $\frac{I_{C}}{I_{E}} = α$ and $\frac{I_{C}}{I_{B}} = β$ . If $α$ varies between $\frac{20}{21}$ and $\frac{100}{101}$ , then the value of $β$ lies between

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1- 10

0.95 – 0.99

20 – 100

200 – 300

answer is C.

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Detailed Solution

$β = \frac{α}{1 - α}$

$β = \frac{\frac{20}{21}}{1 - \frac{20}{21}} = 20$

$β = \frac{\frac{100}{101}}{1 - \frac{100}{101}} = 100$

$s o β l i e s b e t w e e n 20 - 100$

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In a transistor if ICIE=α and ICIB=β. If α varies between 2021 and 100101, then the value of β lies between

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In a transistor if $\frac{I_{C}}{I_{E}} = α$ and $\frac{I_{C}}{I_{B}} = β$ . If $α$ varies between $\frac{20}{21}$ and $\frac{100}{101}$ , then the value of $β$ lies between