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In a transistor the current amplification factor $α$ is 0.9. The transistor is connected in common emitter configuration, the change in collector current when base current changes by 4 mA is

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24 mA

36 mA

12 mA

4 mA

answer is D.

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Detailed Solution

for a transistor current gain $β = \frac{∆ I_{c}}{∆ I_{b}} and β = \frac{α}{1 - α} = \frac{0.9}{1 - 0.9} = 9$

$∆ I_{c} = β ∆ I_{b} = 9 \times 4 mA = 36 mA$

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