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Q.

In a transistor the current amplification factor α is 0.9. The transistor is connected in common emitter configuration, the change in collector current when base current changes by 4 mA is

 

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a

24 mA                    

b

36 mA

c

12 mA                    

d

4 mA                                  

answer is D.

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Detailed Solution

for a transistor current gain β=∆Ic∆Ib  and β=α1-α=0.91-0.9=9

∆Ic=β∆Ib=9×4 mA=36 mA

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