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Q.

In a triangle ABC, if A=60° then the value of 1+ac+bc1+cbab is 

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answer is 3.

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Detailed Solution

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Given that in triangle ABC

The measure of angle A is 60°

We know that from the half angle formule

sinA2=ss-abc

Squaring on both  sides

Sin2A2=2s2s-2a4bc =a+b+cb+c-a4bc434=1+ac+bc1+cb-ab

Therefore, 1+ac+bc1+cb-ab=3

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