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Q.

In a triangle $X Y Z$ , if the internal bisector of $∠ X$ meets $YZ$ in $P$ then

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a

$\frac{X Y}{P Z} = \frac{X Z}{Y P}$

b

$\frac{X Y}{X Y} = \frac{Y P}{Y Z}$

c

$\frac{X Y}{X Z} = \frac{P Z}{Y P}$

d

$\frac{X Y}{X Z} = \frac{Y P}{P Z}$

answer is A.

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Detailed Solution

Question Image

By vertical angle bisector theorem

$\frac{X Y}{X Z} = \frac{Y P}{P Z}$

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