In a two-digit number, the digit at the ten’s place is twice the digit at units’ place. If the number obtained by interchanging the digits is added to the original number, the sum is 66. Find the number.

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answer is A.

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Detailed Solution

Concept: To create the two-digit number, first suppose the digits at the unit and ten places. Then, we create equations between the two presumptions using the criteria provided in the problem. To acquire the desired result, solve them.
A two-digit number that has the digit at the ten place value being twice as valuable as the digit at the one place value is provided as the problem.
Additionally, when the original number is added to the result of modifying the place values of the digits, the result is

66 .

Finding the two-digit number is our goal.
Assume that the digit at position one is x and the d[19]igit at position ten is y.
The two-digit number is therefore represented as

10 y + x = 10 y + x .

The digit at the ten place value is twice as valuable as the digit at the one place value, according to the problem's first condition.

\Rightarrow y = 2 x (1)

Thus, we arrive at our first equation.
Utilising the second condition listed in the problem in a similar manner
When the original number is added to the result of modifying the place values of the digits, the result is a sum of