Q.

In a two dimensional motion of a particle, the particle moves from point A, position vector 15 to point B, position vector r2. If the magnitudes of these vectors are respectively,  r1=3  and  r2=4 and the angles they make with the x-axis are θ1=750  and  150, respectively, then find the magnitude of the displacement vector 

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a

15

b

13

c

17

d

15

answer is B.

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Detailed Solution

Displacement = AB

Angle between  r1  and  r2

θ=750150=600

From figure,

AB2=r12+r222r1r2cosθ

=32+422×3×4cos600=13

AB=13

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