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Q.

In a two dimensional space the potential energy function of the only conservative force acting on a particle of mass m=0.1  kg is given by  U=2(x+y)  joule [ x & y are in metres]. The particle is being moved on a circular path  x2+y2=4  with constant speed  V=1 m/s. The y component of the net external force [other them the conservative force] that must be acting on the particle at [0,4] in newton’s is _______

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answer is 1.98.

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Detailed Solution

Fx=dudx   Fy=dudy

 Hence conservative force  Fc=2i^2j^ 
At (0,4)     Fxt+Fc=mv2R[j^]
Fxt=2i^1.975j^

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