In a uniform circular motion, if the radius decreases to half of its initial value, then the angular velocity

Given that in an U.C.M

Radius = r, angular velocity $\omega$

Now radius ${\text{r}}^{\text{|}}=\frac{\text{r}}{\text{2}}$ , angular velocity ${\omega }^{|}=?$

Since v is constant

We can have

$\text{r}\omega ={\text{r}}^{\text{|}}{\omega }^{|}\Rightarrow \text{r}\omega =\frac{\text{r}}{\text{2}}{\omega }^{|}$

$\therefore {\omega }^{|}=2\omega$

That is increases to 2 times.