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Q.

In a vernier calipers, 10 division of the vernier scale are matching with 9 divisions of the main scale. When a sphere is placed in between the jaws, the zero of the vernier scale lies between 15 mm and 16 mm divisions of the main scale and the 6th division of the vernier scale coincides with one of the main scale divisions. The diameter of the sphere is (one main scale division is 1 mm)

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a

16.06 mm

b

15.6 mm

c

16.6 mm

d

15.06 mm

answer is A.

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Detailed Solution

10 vernier scale divisions = 9 mm
1 vernier scale division = 0.9 mm
$\Rightarrow least count = 1 MSD - 1 VSD$
=1mm-0.9mm= 0.1 mm
Thickness of the object = (main scale reading) + (vernier scale Reading) (least count )
So thickness of the object ,
= 15 mm + (6) (0.1mm ) = 15.6 mm

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