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Q.

In a Vernier calipers each cm on the main scale is divided into 20 equal parts, if tenth vernier scale division coincides with ninth main scale division then, the value of vernier constant will be

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a

0.05 mm

b

0.06 mm

c

0.07 mm

d

0.08 mm

answer is A.

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Detailed Solution

Given the $1 c m$ in main scale is divided into 20 equal parts 1 main scale division
$1 M S D = \frac{1}{20} c m = 0.05 c m 10 V S D = 9 M S D 1 V S D = \frac{9}{10} M S D V C = 1 M S D - 1 V S D V C = 1 M S D - \frac{9}{10} M S D = \frac{1}{10} M S D = \frac{1}{10} (0.05) c m = 0.005 c m = 0.05 m m$

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