In a vessel, two equilibrium are simultaneously established at the same temperature as follows

$\begin{array}{r}{\mathrm{N}}_2\left(g\right)+3{\mathrm{H}}_2\left(g\right)\rightleftharpoons 2{\mathrm{NH}}_3\left(g\right);K_{P_1}\\ {\mathrm{N}}_2\left(g\right)+2{\mathrm{H}}_2\left(g\right)\rightleftharpoons {\mathrm{N}}_2{\mathrm{H}}_4\left(g\right);K_{P_2}\end{array}$

Initially, vessel contains ${\mathrm{N}}_2$ and ${\mathrm{H}}_2$ in molar ratio $9:13.$ The equilibrium pressure is $7P_0$ in which pressure due to ${\mathrm{NH}}_3$ is $P_0$ and due to ${\mathrm{H}}_2\text{ is }2P_0$ Find the value of $\frac{K_{P_2}}{K_{P_1}}$