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In a ΔXYZ, which of the given condition holds?

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XY + ZX < YZ

XY − YZ < ZX

XY + YZ < ZX

XY − YZ > ZX

answer is B.

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Detailed Solution

We know that the sum of the lengths of any two sides of a triangle is greater than the length of the third side.

So, in ΔXYZ,

XZ + XY > YZ

XZ + YZ > XY

XY + YZ > XZ

We also know that the difference between the length of any two sides of a triangle is smaller than the length of the third side.

So, in ΔXYZ,

XZ − XY < YZ

XZ − YZ < XY

XY − YZ < XZ

Hence, from the given options, XY − YZ < ZX is the correct alternative.

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