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In a Young’s double slit experiment 12 fringes are observed to be formed in a certain segment of the screen when light of wavelength 600 nm is used. If the wavelength is changed to 400nm, number of fringes observed in the same segment of the screen is given by

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answer is B.

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Detailed Solution

fringe width= $\frac{λ D}{d}$
$12 λ_{1} = k λ_{2}$ . Hence $k = \frac{12 \times 600}{400} = 18$

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