In a young’s double slit experiment, a light of wavelength 660 nm is used. The slit separation is 4×10−5 m. The angle that locates the second order bright fringe is

Δx=dsinθ⇒nλ=dsinθ⇒θ=sin-1nλd⇒θ=sin-12×660×10-94×10-5=sin-1(33×10-3)

In a young’s double slit experiment, a light of wavelength 660 nm is used. The slit separation is 4×10−5 m. The angle that locates the second order bright fringe is

Δx=dsinθ⇒nλ=dsinθ⇒θ=sin-1nλd⇒θ=sin-12×660×10-94×10-5=sin-1(33×10-3)

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In a young’s double slit experiment, a light of wavelength 660 nm is used. The slit separation is $4 \times 10^{- 5}$ m. The angle that locates the second order bright fringe is

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$\sin^{- 1} (66 \times 10^{- 3})$

$\sin^{- 1} (55 \times 10^{- 3})$

$\sin^{- 1} (33 \times 10^{- 3})$

$\sin^{- 1} (44 \times 10^{- 3})$

answer is C.

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Detailed Solution

$Δx = dsinθ$

$\Rightarrow nλ = dsinθ$

$\Rightarrow θ = \sin^{- 1} (\frac{nλ}{d})$

$\Rightarrow θ = \sin^{- 1} (\frac{2 \times 660 \times 10^{- 9}}{4 \times 10^{- 5}}) = \sin^{- 1} (33 \times 10^{- 3})$

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In a young’s double slit experiment, a light of wavelength 660 nm is used. The slit separation is 4×10−5 m. The angle that locates the second order bright fringe is

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In a young’s double slit experiment, a light of wavelength 660 nm is used. The slit separation is $4 \times 10^{- 5}$ m. The angle that locates the second order bright fringe is