Q.

In a Young’s double-slit experiment, the slit separation is 0.5 mm and the screen is 0.5 m away from the slit. For a monochromatic light of wavelength 500 nm, the separation of 3rd maxima from the 2nd minima on the other side of the central maxima is (in μm)

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answer is 2250.

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Detailed Solution

d=0.5 mm  and  D=0.5 m
Separation  =3β+1.5β=4.5β
=4.5×λDd=2.25mm

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In a Young’s double-slit experiment, the slit separation is 0.5 mm and the screen is 0.5 m away from the slit. For a monochromatic light of wavelength 500 nm, the separation of 3rd maxima from the 2nd minima on the other side of the central maxima is (in μm)