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In a Young’s double-slit experiment using slits of unequal widths, the intensities on the screen due to the slits are in the ratio 4 : 9 when the slits are used separately. When they are used together, the ratio of the intensity at a dark fringe to the intensity at a bright fringe on the screen will be

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4 : 9

1 : 9

9 : 16

1 : 25

answer is D.

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Detailed Solution

$\frac{A_{1}}{A_{2}} = \frac{2}{3} and \frac{I_{max}}{I_{min}} = {(\frac{3 + 2}{3 - 2})}^{2}$

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