In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is ________ nm.

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answer is 630.

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Detailed Solution

$\begin{array}{l} λ = 560 \times 10^{- 9} \\ B_{1} = 7 .2 \times 10^{- 3} \\ B_{2} = 8 .1 \times 10^{- 3} \\ \frac{B_{1}}{B_{2}} = \frac{λ_{1}}{λ_{2}} \\ \Rightarrow λ_{2} = \frac{560 \times 10^{- 9} \times 8 .1 \times 10^{- 3}}{7 .2 \times 10^{- 3}} \\ = 6 .3 \times 10^{- 7} m \\ = 630 nm \end{array}$

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