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Q.

In a Young's double slit experiment, first maxima is observed at a fixed point P on the screen. Now the screen is continuously moved away from the plane of slits. The ratio of intensity at point P to the intensity at point O (centre of the screen)

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a

keeps on decreasing

b

remains constant

c

first decreases and then becomes constant

d

first decreases and then increases

answer is C.

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Detailed Solution

Ip=Imax2[1+cosϕ]=Imax21+cos2πyβ

Where β=d

First maxima is observed at P i.e., cos2πyβ=1; as D increases D will increase, the value of cos2πyβ should be negative hence the ratio IP/Imax starts decreasing but starts increasing again as cos2πyβ again starts becoming positive.

 

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