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Q.

In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :

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a

1.7º

b

0.57º

c

0.17º

d

0.07º

answer is D.

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Detailed Solution

$a n g u l a r f r i n g e w i d t h = \frac{β}{D} = \frac{λ}{d} = \frac{500 \times 10^{- 9}}{0.05 \times 10^{- 3}} = 10^{- 2} r a d = 0.57 \deg$

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In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :