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In a Young’s interference experimental arrangement, the yellow light is composed of two wavelengths 5890 $\overset{0}{A}$ and 5895 $\overset{0}{A}$ . The distance between the two slits is 10^–3 m and screen is placed 1 m away. Upto what order can fringes be seen?

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Detailed Solution

When the maxima of one wavelength coincides with minima of the other, the fringes will disappear

\frac{{n\left( {5895} \right)D}}{d} = \frac{{\left( {n + \frac{1}{2}} \right)5890D}}{d}\

Hence fringes will be visible upto 589 order of wavelength 5895 $\overset{0}{A}$

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