In a zener diode (V_z=5V and I_z =10mA) is connected in series with a resistance and 20V is applied across the combination, then the maximum series resistance one can use without spoiling zener action is (in $k Ω$ ).

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Detailed Solution

$I_{s} = I_{z} + I_{L}$

For $I_{s}$ to be minimum, $I_{L}$ should be zero.

Thus, minimum value of $I_{s}$ is $I_{s_m i n} = I_{z} = 10 m A$

$V_{s} = V - V_{z} = 2 - - 5 = 15 V$

$R_{s_m a x} = \frac{V_{s}}{I_{s_m i n}} = \frac{15}{10} \times 10^{3} Ω = 1.5 k Ω$

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