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In a $0.2$ molal aquous solution of a weak acid $H X$ the degree of dissociation is $0.25$ . The freezing points of the solutions will be nearest to: $(K_{f} = 1.86 k K g m o l^{- 1})$

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$- {0.48}^{0} C$

$- {0.26}^{0} C$

$- {0.465}^{0} C$

${0.465}^{0} C$

answer is D.

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Detailed Solution

$\begin{array}{l} i = 1 + α \Rightarrow 1.25 \\ △ T_{f} = K_{f} . m . i \Rightarrow i = 0.633 : \\ i = 1 - α + \frac{α}{2} \Rightarrow α = - {0.465}^{0} C \end{array}$

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