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Q.

In a ABC , the sides BC=5,CA=4,AB=3 . If A(0,0) and the internal bisector of angle A meets BC in D127,127 then incentre of  ABC is

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a

(2, 2)

b

(2, 3)

c

(3, 2)

d

(1, 1)

answer is D.

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Detailed Solution

I divides AD in the ratio b + c : a,

    Incentre=7127,127+5(0,0)12=(1,1)

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